1225:Palindrome(II)

Problem Link:

 

<Source Code>
#include<stdio.h>

#include<string.h>
char num[100];

int main(){
int tc;scanf(“%d”,&tc);
for(int tid = 1; tid <=tc; ++tid){
scanf(“%s”,num);
int p = 1;
int s = strlen(num);

for(int i = 0; i< s; ++i)
if(num[i] != num[s-i-1]){
p = 0;
break;
}

if(p) printf(“Case %d: Yes\n”, tid);
else printf(“Case %d: No\n”, tid);

}
return 0;
}

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About waprogramming

I am in CSE,from CUET
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